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Two identical containers A and B having the same volume of an ideal gas at the same temperature have the mass of the gas as m 1 and m 2 respectively and 2 m 1 = 3 m 2 . The gas in each cylinder expands isothermally to double of its volume. If the change in pressure in A is 300 Pa , then the change in pressure in B is

Options

  1. A200   Pa
  2. B300   Pa
  3. C400   Pa
  4. D500   Pa

Correct answer

A. 200   Pa

Step-by-step solution

2 m 1 = 3 m 2 P 1 V = m 1 M R T a n d P 2 V = m 2 M R T = 2 3 m 1 M R T P 1 P 2 = 3 2 ………(i) The process is isothermal P 1 V 1 = P 2 V 2 Hence, ∆ P 1 = P 1 - P 1 2 ⇒ P 1 = 2 ∆ P 1 ∆ P 2 = P 2 - P 2 2 = P 2 2 = 1 2 2 3 P 1 = P 1 3 ∆ P 2 = 2 3 ∆ P 1 = 2 3 . 300 ∆ P 2 = 200 P a

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