NTA Abhyas JEE Main2020PhysicsThermodynamicsPractice
An ideal gas heat engine operates in a Carnot's cycle between 227 ° C and 127 ° C . It absorbs 6 × 10 4 J at the higher temperature. The amount of heat converted into work is
Options
- A1.6 × 10 4 J
- B1.2 × 10 4 J
- C4.8 × 10 4 J
- D3.5 × 10 4 J
Correct answer
B. 1.2 × 10 4 J
Step-by-step solution
Using the relation, W Q 1 = Q 1 - Q 2 Q 1 W Q 1 = 1 - Q 2 Q 1 W Q 1 = 1 - T 2 T 1 ∵ Q 1 Q 2 = T 1 T 2 W = Q 1 1 - T 2 T 1 ∴ W = 6 × 10 4 1 - ( 127 + 273 ) ( 227 + 273 ) W = 6 × 10 4 1 - 400 500 = 6 × 10 4 × 100 500 = 1.2 × 10 4 J