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An ideal gas expands isothermally from a volume V 1 to V 2 and then compressed to original volume V 1 adiabatically. The initial pressure is P 1 and final pressure is P 3 . The total work done is W . Then:

Options

  1. AP 3 > P 1 ,   W > 0
  2. BP 3 < P 1 ,   W < 0
  3. CP 3 > P 1 ,   W < 0
  4. DP 3 = P 1 ,   W = 0

Correct answer

C. P 3 > P 1 ,   W < 0

Step-by-step solution

From the graph it is clear that P 3 > P 1 . Since the area under adiabatic process B C E D is greater than that of the isothermal process A B C D . Therefore net word done W = W i + - W A ∵   W A > W i ⇒ W < 0

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