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One mole of an ideal gas as taken from state A to state B by three different processes ( a ) ACB , ( b ) ADB and ( c ) AEB as shown in the P - V diagram. The heat absorbed by the gas is

Options

  1. AGreater in process (b) than in (a)
  2. BThe least in process (b)
  3. CThe same in (a) and (c)
  4. DLess in (c) than in (b)

Correct answer

D. Less in (c) than in (b)

Step-by-step solution

Heat absorbed by gas in three processes is given by Q ACB = Δ U + W ACB Q ADB = Δ U Q AEB = Δ U + W AEB The change in internal energy in all the three cases is the same and W ACB is positive, W AEB is negative. Hence Q ACB > Q ADB > Q AEB

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