A lead bullet of 10 g travelling at 300 m s - 1 strikes against a block of wood comes to rest. Assuming 50 % of heat is absorbed by the bullet, the increase in its temperature (Specific heat of lead = 150 J k g - 1 k - 1 )

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Correct answer: C. 150 &#160;&#8451;

Here, m = 10 g = 10 - 2 kg v = 300 m s - 1 , Δ θ = ?, C = 150 J k g − 1 K − 1 Q = 50 100 1 2 m v 2 = 1 4 × 10 - 2 300 2 = 225 J From Q = m C Δ θ θ = Q C m = 225 150 × 10 - 2 = 150 ℃

A lead bullet of 10 g travelling at 300 m s - 1 strikes against a block of wood comes to rest. Assuming 50 % of heat is absorbed by the bullet, the increase in its temperature (Specific heat of lead = 150 J k g - 1 k - 1 )

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