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In a given process of an ideal gas, dW = 0 and dQ < 0 . Then for the gas

Options

  1. AThe temperature will decrease
  2. BThe volume will increase
  3. CThe pressure will remain contain
  4. DThe temperature will increase

Correct answer

A. The temperature will decrease

Step-by-step solution

From first law of thermodynamics, dQ = dU + dW dQ = dU , if dW = 0 Since, dQ < 0 Therefore, dU < 0 or U Final < U initial so, the temperature will decrease. Note: Internal energy U of an ideal gas depends only on the temperature of the gas. The internal energy of n moles of an ideal gas is given by nC v dT

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