NTA Abhyas JEE Main2020PhysicsThermodynamicsPractice
One mole of an ideal gas is taken along the process in which P V x = constant. The graph shown represents the variation of molar heat capacity of such a gas with respect to x . The values of c ' and x ' . respectively, are given by
Options
- A5 2 R , 5 2
- B5 2 R , 5 3
- C7 2 R , 7 2
- D5 2 R , 7 5
Correct answer
B. 5 2 R , 5 3
Step-by-step solution
For P V x = constant C = C V + R − x + 1 At x = ∞ , C = 3 2 R from PV x = constnat ⇒ P 1 / x V = another constant so at x = ∞ , C v = 3 2 R hence C = C v = 3 2 R and then C p = C v + R = 5 2 R at x = 0, P = constant and C = C' hence C ′ = C p = 5 2 R at x = x', C = 0, so the process is adiabatic, hence x ′ = C p C v = 5 3