NTA Abhyas JEE Main2020PhysicsThermodynamicsPractice
A gas is heated in such a way that its pressure and volume both becomes double. Then by decreasing temperature, some of the molecules of air has been added in a container to maintain the doubled volume and pressure. Assuming 1 4 th of the initial number of moles has been added in for the purpose. By what fraction the temperature must have been raised finally of initial absolute temperature?
Options
- A4 t i m e s
- B16 5 t i m e s
- C4 5 t i m e s
- D1 5 t i m e s
Correct answer
B. 16 5 t i m e s
Step-by-step solution
I initially : Pressure P volume V temp T moles n. II on 2 P 2 V then temperature heating becomes 4 T After decreasing temperature : III Pressure volume Temperature moles 2 P 2 V T ′ (assume) n + n 4 = 5 n 4 for I I case ideal gas equation 2 P × 2 V = n × R × 4 T III case 2 P × 2 V = 5 n 4 × R × T ′ ⇒ T ′ = 16 5 T