NTA Abhyas JEE Main2020PhysicsThermodynamicsPractice
One mole of ideal gas goes through process P = 2 V 2 1 + V 2 then change in temperature of the gas when volume changes from V = 1 m 3 to 2 m 3 is:
Options
- A- 4 5 R   K
- B11 5 R   K
- C- 5 2 R   K
- D2 K
Correct answer
B. 11 5 R   K
Step-by-step solution
P = 2 V 2 1 + V 2 P 1 = 1 P 2 = 8 5 Δ T = T 2 - T 1 = P 2 V 2 n R - P 1 V 1 n R = 11 5 R