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If 2 moles of diatomic gas and 1 mole of monatomic gas are mixed, then the ratio of specific heats for the mixture is

Options

  1. A7 3
  2. B5 4
  3. C19 13
  4. D15 19

Correct answer

C. 19 13

Step-by-step solution

μ 1 = 1 , γ 1 = 5 / 3 (for monatomic gas) and μ 2 = 2 , γ 2 = 7 / 5 (for diatomic gas). Form formula γ mixture = μ 1 γ 1 γ 1 - 1 + μ 2 γ 2 γ 2 - 1 μ 1 γ 1 - 1 + μ 2 γ 2 - 1 = 1 × 5 3 5 3 - 1 + 2 × 7 5 7 5 - 1 1 5 3 - 1 + 2 7 5 - 1 = 5 3 + 7 3 2 + 5 = 1 9 1 3

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