NTA Abhyas JEE Main2020PhysicsThermodynamicsPractice
One mole of a monoatomic gas γ 1 = 5 3 is mixed with one mole of a diatomic gas γ 2 = 7 5 . What is the value of γ for the mixture?
Correct answer
1.5
Step-by-step solution
For the mixture, γ m i x = μ 1 γ 1 γ 1 - 1 + μ 2 γ 2 γ 2 - 1 μ 1 γ 1 - 1 + μ 2 γ 2 - 1 = 1 × 5 3 5 3 - 1 + 1 × 7 5 7 5 - 1 1 5 3 - 1 + 1 7 5 - 1 = 3 2 = 1.5