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AIIMS 2012
Exam
AIIMS
Year
2012
Subject
Chemistry
Chapter
Solid State

AIIMS 2012 · Chemistry · Solid State

CsCl has b c c arrangement. Its unit cell edge length is 400 pm ....

CsCl\mathrm{CsCl} has bccb c c arrangement. Its unit cell edge length is 400pm400 \mathrm{pm}. Its inter-ionic distance is

Options

  1. A400pm400 \mathrm{pm}
  2. B800pm800 \mathrm{pm}
  3. C3×100pm\sqrt{3} \times 100 \mathrm{pm}
  4. D32×400pm\frac{\sqrt{3}}{2} \times 400 \mathrm{pm}

Correct answer

C. 3×100pm\sqrt{3} \times 100 \mathrm{pm}

Step-by-step solution

In the body-centred cubic unit cell, a3=4ra \sqrt{3}=4 r r=a34=40034=1003pmr=\frac{a \sqrt{3}}{4}=\frac{400 \sqrt{3}}{4}=100 \sqrt{3} \mathrm{pm}
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