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NTA Abhyas NEET2020ChemistryChemical EquilibriumPractice

15 moles of H 2 and 5.2 moles of I 2 are mixed and allowed to attain equilibrium at 500 o C . At equilibrium, the number of moles of H I is found to be 10 mole. The equilibrium constant for the formation of H I is

Options

  1. A50
  2. B15
  3. C100
  4. D25

Correct answer

A. 50

Step-by-step solution

H 2 + I 2 ⇌ 2 H I 15 5.2 0 15 − 5 5.2 − 5 10 Equilibrium constant K c = H I 2 H 2 [ I 2 ] = 10 × 10 10 × 0.2 = 50

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