For the reversible reaction, N 2 ( g ) + 3 H 2 ( g ) ⇌ 2 N H 3 ( g ) at 500 ° C , the value of K p is 1.44 × 10 − 5 when partial pressure is measured in atmosphere. The corresponding value of K c , with concentration in mole litre - 1 , is –

Step-by-step solution

Δ n g = n p − n r n p = number of moles of products (gaseous) n r = number of moles of reactants (gaseous) Δ n g = 2 − 4 = − 2 K C = K P RT Δ n g K c = 1.44 × 10 − 5 ( 0.082 × 773 ) − 2 (T in K and R in L atm mole -1 K - 1 ).