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The following equilibrium constants are given: N 2 + 3 H 2 ⇌ 2 NH 3 ; K ⁡ 1 N 2 + O 2 ⇌ 2 NO ; K ⁡ 2 H 2 + 1 / 2 O 2 ⇌ H 2 O ; K ⁡ 3 The equilibrium constant for the oxidation of 2 mole NH 3 by oxygen to give NO is

Options

  1. AK 2 K 3 2 K 1
  2. BK 2 2 K 3 K 1
  3. CK 1 K 2 K 3
  4. DK 2 K 3 3 K 1

Correct answer

D. K 2 K 3 3 K 1

Step-by-step solution

N 2 + 3 H 2 ⇌ 2NH 3 K 1 = NH 3 2 N 2 H 2 3 … i N 2 +O 2 ⇌ 2 NO ; K 2 = NO 2 N 2 O 2 … ii H 2 + 1 / 2 O 2 ⇌ H 2 O ; K 3 = H 2 O H 2 O 2 1 / 2 … iii For the reaction, 2 NH 3 + 5 2 O 2 ⇌ 2 NO + 3 H 2 O K ⁡ = NO 2 H 2 O 3 NH 3 2 O 2 5 / 2 = NO 2 N 2 O 2 × H 2 O 3 H 2 3 O 2 3 / 2 × N 2 H 2 3 NH 3 2 = K 2 × K 3 3 K 1

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