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Given that the equilibrium constant for the reaction 2 S O 2 ( g ) + O 2 ( g ) ⇌ 2 S O 3 ( g ) has a value of 278 at a particular temperature. What is the value of the equilibrium constant for the following reaction at the same temperature? S O 3 ( g ) ⇌ S O 2 ( g ) + 1 2 O 2 ( g )

Options

  1. A1.8 × 10 – 3
  2. B3.6 × 10 – 3
  3. C6.0 × 10 – 2
  4. D1.3 × 10 – 5

Correct answer

C. 6.0 × 10 – 2

Step-by-step solution

At the given temperature, 2 S O 2 + O 2 ⇌ 2 S O 3 K = [ S O 3 ] 2 [ S O 2 ] 2 [ O 2 ] S O 3 ⇌ S O 2 + 1 2 O 2 K ′ = [ S O 2 ] [ O 2 ] 1 2 [ S O 2 ] K ′ = 1 K = 1 278 = 35.97 × 10 − 4 = 6 × 10 − 2

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