NTA Abhyas NEET2020ChemistryChemical EquilibriumPractice
For the following equilibrium in gaseous phase, N 2 O 4 ⇌ 2 N O 2 N O 2 is 50 % of the total volume, when equilibrium is set up. Hence, percent dissociation of N 2 O 4 is:
Options
- A50 %
- B25 %
- C66.66 %
- D33.33 %
Correct answer
D. 33.33 %
Step-by-step solution
N 2 O 4 ⇋ 2 N O 2 I n i t i a l l y 1 0 A t e q u i l i b r i u m 1 - x 2 x Total number of moles = 1 - x + 2 x = 1 + x ∴ % o f N O 2 by volume = 2 x 1 + x × 100 = 50 i.e. x = 1 3 (i.e. 0.333) Hence, % dissociation = 33.33 %