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NTA Abhyas NEET2020ChemistryChemical EquilibriumPractice

For a given exothermic reaction, K p and K P ' are the equilibrium constants at temperatures T 1 and T 2 , respectively. Assuming that heat of reaction is constant in temperature range between T 1 and T 2 , it is readily observed that T 2 > T 1

Options

  1. AK P = 1 K P '
  2. BK P < K P '
  3. CK P = K P '
  4. DK P > K P '

Correct answer

D. K P > K P '

Step-by-step solution

log ⁡ k p k p ' = ∆ H 2.303 R 1 T 1 - 1 T 2 for exothermic reaction ∆ H = - v e T 2 > T 1 In exothermic reactions on increasing temperature value of equilibrium decreases. So, K p > K p '

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