NTA Abhyas NEET2020ChemistryChemical EquilibriumPractice
If pH of a saturated solution of B a ( O H ) 2 is 12, the value of its K ( s p ) is
Options
- A5.00 × 1 0 - 7 M 3
- B4.00 × 1 0 - 6 M 3
- C4.00 × 1 0 - 7 M 3
- D5.00 × 1 0 - 6 M 3
Correct answer
A. 5.00 × 1 0 - 7 M 3
Step-by-step solution
As p H = 12 p O H = 14 - 12 = 2 [ O H- ] = 1 0 - 2 M = 0.01 M In case of B a ( O H ) 2 s ⇌ B a + 2 s + 2 O H - 2 2 s As 2 s = 0.01 mole / L s = 0.01 2 = 5 × 1 0 - 3 mole / L Ksp for B a ( O H ) 2 = 4 s 3 = 4 ( 5 × 1 0 - 3 ) 3 = 5 × 1 0 - 7 M 3