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In a 10 l i t r e box 2.5 m o l e hydroiodic acid is taken. After equilibrium 2 H I ⇌ H 2 + I 2 the concentration of H I is found to be 0.1 mol L − 1 . The concentration of H 2 at equilibrium in mol L - 1 , is

Options

  1. A2.4
  2. B0.15
  3. C1.5
  4. D7.5 × 1 0 - 2

Correct answer

D. 7.5 × 1 0 - 2

Step-by-step solution

0.25 - 2 at equilibrium 0.25 - 2 x = 0.1 x = 7.5 × 1 0 - 2

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