NTA Abhyas NEET2020ChemistryChemical EquilibriumPractice
When heated, ammonium carbamate decomposes as follows N H 4 C O O N H 2 ( s ) ⇌ 2 N H 3 ( g ) + C O 2 ( g ) At a certain temperature, the equilibrium pressure of the system is 0.318 atm, K p for the reaction is
Options
- A0.128
- B0.146
- C4.76 × 1 0 - 3
- D2.24 × 1 0 - 2
Correct answer
C. 4.76 × 1 0 - 3
Step-by-step solution
N H 4 C O O N H 2 ( s ) E q . p r e s s u r e ⇌ 2 N H 3 ( g ) 2 P + C O 2 ( g ) P 3 P = 0.318 P = 0.106 P N H 3 = 2 × 0.106 = 0.212 P C O 2 = 0.106 k p = P N H 3 2 . P C O 2 = 0.212 × 0.212 × 0.106 = 0.00476 = 4.76 × 1 0 - 3