NTA Abhyas NEET2020ChemistryChemical EquilibriumPractice
The value of l o g 10 K for a reaction A ⇌ B is (Given: Δ r H o 298 K = - 54.07 k J m o l - 1 , Δ r S o 298 K = 10 J K - 1 m o l - 1 and R = 8.314 J K - 1 m o l - 1 ; 2.303 × 8.314 × 298 = 5705 )
Options
- A90
- B100
- C5
- D10
Correct answer
D. 10
Step-by-step solution
Δ G o = Δ H o - T Δ S o = - 54.07 × 1000 – 298 × 10 = - 57050 J m o l - 1 Δ G ° = - 2.303 R T l o g 10 K - 57050 = - 5705 l o g 10 K l o g 10 K = 10