NTA Abhyas NEET2020ChemistryChemical EquilibriumPractice
For the reaction, N 2 O 4 ( g ) ⇌ 2 N O 2 ( g ) the degree of dissociation at equilibrium is 0.4 at a pressure of 1 atm. The value of K p is
Options
- A0.64 atm
- B0.60 atm
- C0.19 atm
- D0.762 atm
Correct answer
D. 0.762 atm
Step-by-step solution
K p = P N O 2 2 P N 2 O 4 = 4 α 2 1 - α 2 × P ⇒ K p = 4 × 0.4 2 1 - 0.4 2 × 1 ∴ K p = 0.762 a t m