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For the equilibrium L i C l . 3 N H 3 ( s ) ⇌ L i C l . N H 3 ( s ) + 2 N H 3 ( g ) ; K P = 9 a t m 2 at 37 ° C . A 5 L vessel contains 0.1 mole of L i C l . N H 3 . How many mole of N H 3 should be added to the flask at this temperature derive the backward reaction for completion? (use R = 0.082 atm-L/mol K)

Options

  1. A0.49
  2. B0.59
  3. C0.69
  4. D0.79

Correct answer

D. 0.79

Step-by-step solution

L i C l . 3 N H 3 ( s ) - 0.1 ⇌ L i C l . N H 3 ( s ) 0.1 - + 2 N H 3 ( g ) a a - 0.2 K P = 9 = P N H 3 2 P N H 3 = 3 PV = nRT 3 × 5 = ( a - 0.2 ) 0.082 × 310 a = 0.79

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