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The following equilibrium constants are given N 2 + 3 H 2 ⇌ 2 N H 3 ; K 1 N 2 + O 2 ⇌ 2 N O ; K 2 H 2 + 1 2 O 2 ⇌ H 2 O ; K 3 The equilibrium constant for the oxidation of 2 mol of N H 3 to give NO is

Options

  1. AK 1 . K 2 K 3
  2. BK 2 . K 3 3 K 1
  3. CK 2 . K 3 2 K 1
  4. DK 2 2 . K 3 K 1

Correct answer

B. K 2 . K 3 3 K 1

Step-by-step solution

N 2 + 3 H 2 ⇌ 2 N H 3 ; K 1 K 1 = [ N H 3 ] 2 [ N 2 ] [ H 2 ] 3 N 2 + O 2 ⇌ 2 N O ; K 2 H 2 + 1 2 O 2 ⇌ H 2 O ; K 3 K 2 = [ N O ] 2 [ N 2 ] [ O 2 ] ; K 3 = [ H 2 O ] [ H 2 ] [ O 2 ] 1 / 2 Now, oxidation of N H 3 takes places as below 4 N H 3 + 5 O 2 ⇌ 4 N O + 6 H 2 O or 2 N H 3 + 5 2 O 2 ⇌ 2 N O + 3 H 2 O K = [ N O ] 2 [ H 2 O ] 3 [ N H 3 ] 2 [ O 2 ] 5 / 2 K = [ N O ] 2 [ N 2 ] [ O 2 ] . [ N 2 ] [ O 2 ] [ N H 3 ] 2 . [ N 2 ] [ H 2 ] 3 [ N 2 ] [ H 2 ] 3 . [ H 2 O ] 3 [ H 2 ] 3 [ O 2 ] 3 / 2 . [ H 2 ] 3 [ O 2 ] 3 / 2

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