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NTA Abhyas NEET2020ChemistryChemical EquilibriumPractice

HI was heated in a sealed tube at 440 ° C, till the equilibrium was reached. HI was found to be 22% decomposed. The equilibrium constant for dissociation is

Options

  1. A0.282
  2. B0.0796
  3. C0.0199
  4. D1.99

Correct answer

C. 0.0199

Step-by-step solution

So K c = [ H 2 ] [ I 2 ] [ H I ] 2 = 0.11 × 0.11 ( 0.78 ) 2 = 0.0199

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