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For reaction, P C l 3 ( g ) + C l 2 ( g ) ⇌ P C l 5 ( g ) , the value of K c at 250 ° C is 26. The value of K p at this temperature will be

Options

  1. A0.61
  2. B0.57
  3. C0.83
  4. D0.46

Correct answer

A. 0.61

Step-by-step solution

K p = K c ( R T ) Δ n Here K c = 26 , R = 0.0821 L atm m o l - 1 K - 1 , T = 250 + 273 = 523 K , Δ n = 1 - ( 1 + 1 ) = - 1 So K p = 26 × ( 0.0821 × 523 ) - 1 = 0.605 ≃ 0.61

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