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The equilibrium constant K p for a homogenous gaseous reaction is 1 0 - 3 . The standard Gibbs free energy change Δ G ° for the reaction at 27 ° C (using R = 2 cal K - 1 m o l - 1 ) is

Options

  1. A0
  2. B-1.8 kcal
  3. C-4.1454 kcal
  4. D+4.1454 kcal

Correct answer

D. +4.1454 kcal

Step-by-step solution

ΔG = − 2 .303 RT log K p = − 2.303 × 2 × 300 log 10 − 3 = − 2 .303 × 2 × 300 × ( − 3) =   1445 .4   cal   =   4 .1454   kcal

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