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NTA Abhyas NEET2020ChemistryChemical EquilibriumPractice

Four moles of P C l 5 are heated in a closed 4 d m 3 container to reach equilibrium at 400 K. at equilibrium 50% of P C l 5 is dissociated. What is the value of K c in mol/L for the dissociation of P C l 5 into P C l 3 and C l 2 at 400 K is

Options

  1. A0.50
  2. B1.00
  3. C1.15
  4. D0.25

Correct answer

A. 0.50

Step-by-step solution

P C l 5 ⇌ P C l 3 + C l 2 Initial conc. 4 4 0 0 Equili. conc. 2 4 2 4 2 4 K = P C l 3 C l 2 P C l 5 = 2 × 2 × 4 4 × 4 × 2 = 1 2 = 0.5

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