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For the reaction, N 2 g + O 2 ( g ) ⇌ 2 N O ( g ) , the value of K c at 800 ℃ is 0.1. When the equilibrium concentration of both the reactants is 0.5 mole, what is the value of K p at the same temperature?

Options

  1. A0.5
  2. B0.1
  3. C0.01
  4. D0.025

Correct answer

B. 0.1

Step-by-step solution

N 2 g + O 2 ( g ) ⇌ 2 N O ( g ) K c = 0.1 , K p = K c R T ∆ n ∆ n = Number of gaseous product - Number of gaseous reactants ∆ n = 2 - 2 = 0 ∆ n = 0 ∴ K p = K c = 0.1

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