NTA Abhyas NEET2020ChemistryChemical EquilibriumPractice
The equilibrium constant for ionization of aliphatic amine R N H 2 (g) in water is R N H 2 ( g ) + H 2 O ( l ) ⇌ R N H 3 + ( a q ) + O H - ( a q ) is 8 × 1 0 - 6 at 25 ° C . Partial pressure of amine at equilibrium is 0.5 bar. The pOH of the aqueous solution of amine will be
Options
- A2.7
- B4.7
- C3.7
- D5.7
Correct answer
A. 2.7
Step-by-step solution
R N H 2 ( g ) 0.5 + H 2 O ( l ) ⇌ R N H 3 + ( a q ) x + O H - ( a q ) x for it equilibrium constant is given as K = [ R N H 3 + ] [ O H - ] [ R N H 2 ] Here K = 8 × 1 0 - 6 8 × 1 0 - 6 = x × x 0.5 x = 2 × 1 0 - 3 [ O H ] - = 2 × 1 0 - 3 M p O H = - l o g 2 × 1 0 - 3 = 2.7 .