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The equilibrium constants for the reactions are H 3 PO 4   ⇌ K 1   H +   +   H 2 PO 4 − ;   K 1 H 2 PO 4 − ⇌ K 2 H +   +   HPO 4 − 2 ;   K 2 HPO 4 2 −   ⇌ K 2   H +   +   PO 4 3 − ;   K 3 The equilibrium constant for H 3 P O 4 ⇌ 3 H + + P O 4 3 - will be

Options

  1. AK 1 / K 2 / K 3
  2. BK 1 × K 2 × K 3
  3. CK 2 / K 1 K 3
  4. DK 1 + K 2 + K 3

Correct answer

B. K 1 × K 2 × K 3

Step-by-step solution

K 1 = [ H + ] [ H 2 P O 4 - ] [ H 3 P O 4 ] K 2 = [ H + ] [ H P O 4 2 - ] [ H 2 P O 4 - ] K 3 = [ H + ] [ P O 4 3 - ] [ H P O 4 2 - ] Multiplying these three K 1   ×   K 2   ×   K 3   =   H + 3 PO 4 3 − H 3 PO 4 .

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