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At 300 ° C the pressure necessary to obtained 80% dissociation of P C l 5 is numerically equal to

Options

  1. AK P = 17.7 p
  2. BK P = 1.77 p
  3. CK P = 2.22 p
  4. DK P = 177 p

Correct answer

C. K P = 2.22 p

Step-by-step solution

P C l 5 1 1 - 0.8 ⇌ P C l 5 0 0.8 + C l 2 0 0.8 Total number of moles at equilibrium = 0.2 + 0.8 + 0.8 = 1.8 K P = ( P P C l 3 ) ( P C l 2 ) ( P P C l 5 ) = 0.8 1.8 p × 0.8 1.8 p 0.2 1.8 p = 2.22 p

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