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NTA Abhyas NEET2020ChemistryChemical EquilibriumPractice

Suppose the value of the equilibrium constant for the given reaction H 2 ( g ) + I 2 ( g ) ⇌ 2 HI ( g ) at 717 K is 64 , then calculate the same (eq. const.) for the reaction HI ⇌ 1 2 H 2 + 1 2 I 2 .

Options

  1. A64
  2. B8
  3. C1 64
  4. D1 8

Correct answer

D. 1 8

Step-by-step solution

As the reaction is reversed and divided by 2 , the new equilibrium constant will be : K ' C = 1 K C = 1 64 = 1 8

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