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NTA Abhyas NEET2020ChemistryChemical EquilibriumPractice

When sulphur in the form of S 8 is heated at 900 K the initial pressure of 1 atm falls by 29% at equilibrium. This is because of conversion of some S 8 to S 2 . Find the value of equilibrium constant for this reaction.

Options

  1. A2.55 a t m 3
  2. B255 a t m 3
  3. C25.5 a t m 3
  4. DNone

Correct answer

A. 2.55 a t m 3

Step-by-step solution

S 8 ( g ) 1 1 - x ⇌ 4 S 2 ( g ) 0 4 x x = 29 % = 0.29 K p = ( P S 2 ) 4 ( P S 8 ) = ( 4 x ) 2 ( 1 - x ) a t m 3 = ( 4 × 0.29 ) 4 1 - 0.29 = 2.55 a t m 3 .

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