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Decomposition of N 2 O 4 ( g ) takes place as follows N 2 O 4 ( g ) ⇌ 2 N O 2 ( g ) 'D' is the vapour density at initial stage and 'd' is the vapour density at equilibrium. We get following graph when the degree of dissociation ' α ' is plotted against D d What is the value of D d at A?

Options

  1. A0
  2. B0.5
  3. C1
  4. D1.5

Correct answer

C. 1

Step-by-step solution

α = D - d ( n - 1 ) d At 'A', α = 0 So 0 = D - d ( 2 - 1 ) d D d = 1 .

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