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NTA Abhyas NEET2020ChemistryElectrochemistryPractice

During electrolysis of water the volume of O 2 liberated is 2.24 dm 3 . The volume of hydrogen liberated, under same conditions will be

Options

  1. A2.24 d m 3
  2. B1.12 d m 3
  3. C4.48 d m 3
  4. D0.56 d m 3

Correct answer

C. 4.48 d m 3

Step-by-step solution

H 2 O → H 2 + 1 2 O 2 During electrolysis, volumes of O 2 and H 2 liberated are in the ratio of 1 : 2 Hence, volume of H 2 liberated = 2 × 2.24 d m 3 = 4.48 d m 3

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