Electrolysis of a solution of HSO 4 - ions produces S 2 O 8 2 − . Assuming 75% current efficiency, what current should be employed to achieve a production rate of 1 mol of S 2 O 8 2 − per hour ?

Step-by-step solution

2 HSO 4 − → S 2 O 8 2− + 2 H + + 2 e − ​ So, required rate = 1 mol/hr of S 2 O 8 2 − = 2 moles of HSO 4 − = 2 × 9 6 5 0 0 C 3 6 0 0 s = 2 × 9 6 5 3 6 A ≃ 53.6 A So required current = 4 3 × 53.6 A = 71.47 A