NTA Abhyas NEET2020ChemistryElectrochemistryPractice
At 298 K the molar conductivities at infinite dilution ∧ m o of N H 4 C l , K O H and K C l are 152.8, 272.6 and 149.8 S c m 2 m o l - 1 respectively. The ∧ m o of N H 4 O H in S c m 2 m o l - 1 and % dissociation of 0.01 M N H 4 O H with ∧ m = 25.1 S c m 2 m o l - 1 at the same temperature are
Options
- A275.6, 0.91
- B275.6, 9.1
- C266.6, 9.6
- D30, 84
Correct answer
B. 275.6, 9.1
Step-by-step solution
∧ m o N H 4 O H = ∧ m o N H 4 C l + K O H - ∧ m o K C l = 152.8 + 272.6 - 149.8 = 275.6 S c m 2 m o l - 1 Degree of dissociation α = ∧ m ∧ m o = 25.1 275.6 = 0.091 ∴ % degree of dissociation = 9.1%