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Calculate the amount of electricity required to deposit 0.9 g of aluminium by electrolysis of a salt containing its ion, if the electrode reaction is Al 3 + + 3 e - → Al ; ( atomic mass of Al = 2 7 , 1 F = 96500 C )

Options

  1. A9.65 × 10 3 C
  2. B1.93 × 10 4 C
  3. C9.65 × 10 4 C
  4. D4.34 × 10 5 C

Correct answer

A. 9.65 × 10 3 C

Step-by-step solution

Al 3 + + 3 e - → Al ​ 1 mole Al requires 3 mole e - (3 F charge) to dischage on electrode. Also, 1 F = 96500 C. Thus, 27 g of Al require = 3 × 9 6 5 0 0 C 0.9 g of Al requires = 3 × 9 6 5 0 0 C 2 7 × 0.9 = 9650 C . = 9.65 × 10 3 C

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