Electrode potential data given below C l 2 + 2 H 2 O → 2 C l O - + 4 H + + 2 e - ; E ° = - 1.61 v o l t C l O - + 2 H 2 O → C l O 3 - + 4 H + + 4 e - ; E ° = - 0.50 v o l t Based on these data which is the spontaneous reaction.

Step-by-step solution

Given electron potential data is- C l 2 + 2 H 2 O → 2 C l O – + 4 H + + 2 e – ; E ° = - 1.61 Volt C l O – + 2 H 2 O → C l O 3 – + 4 H + + 4 e – ; E ° = - 0.50 Volt For reaction to be spontaneous E 0 reaction should + v e , Thus substracting equation 1 from equation 2 .