NTA Abhyas NEET2020ChemistryElectrochemistryPractice
Molar conductivity of a solution of an electrolyte A B 3 is 150 S c m 2 m o l - 1 . If it ionizes as AB 3 → A 3 + + 3 B − , its equivalent conductivity will be
Options
- A150 ( i n S c m 2 e q - 1 )
- B75 ( i n S c m 2 e q - 1 )
- C50 ( i n S c m 2 e q - 1 )
- D80 ( i n S c m 2 e q - 1 )
Correct answer
C. 50 ( i n S c m 2 e q - 1 )
Step-by-step solution
∧ e q = 1 n + × Z + ∧ m Where, ∧ m = molar conductance n + = number of cations Z + = charge of cation ∧ e q = 1 1 × 3 × 150 = 50