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Molar conductivity of a solution of an electrolyte A B 3 is 150 S c m 2 m o l - 1 . If it ionizes as AB 3 → A 3 + + 3 B − , its equivalent conductivity will be

Options

  1. A150 ( i n S c m 2 e q - 1 )
  2. B75 ( i n S c m 2 e q - 1 )
  3. C50 ( i n S c m 2 e q - 1 )
  4. D80 ( i n S c m 2 e q - 1 )

Correct answer

C. 50 ( i n S c m 2 e q - 1 )

Step-by-step solution

∧ e q = 1 n + × Z + ∧ m Where, ∧ m = molar conductance n + = number of cations Z + = charge of cation ∧ e q = 1 1 × 3 × 150 = 50

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