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When 0.1 mol Mn O 4 2 - is oxidised the quantity of electricity required to completely oxidise M n O 4 2 - to M n O 4 - is (1 F=96500)

Options

  1. A96.50 C
  2. B96500 C
  3. C9650 C
  4. D2 × 965 00 C

Correct answer

C. 9650 C

Step-by-step solution

M n + 6 O 4 - 2 0.1 m o l e → M n + 7 O 4 - + e - 0.1 mole charge required = 0.1 F = 0.1 × 96500 = 9650 C

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