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E ° o f F e 2 + / F e = - 0.44 V , E ° o f C u / C u 2 + = 0 .34 V . Then in the cell

Options

  1. AC u 2 + Oxidizes F e
  2. BF e 2 + oxidizes C u
  3. CC u Reduces F e 2 +
  4. DF e reduces C u 2 +

Correct answer

D. F e reduces C u 2 +

Step-by-step solution

Reduction potential C u 2 + / C u = 0.34 V a n d F e 2 + / F e = – 0.44 V , Thus E 0 f o r F e + C u 2 + → F e 2 + + C u is 0.78 Hence, Fe reduces C u 2 +

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