Consider the change in oxidation state of Bromine corresponding to different emf values as shown in the diagram below Then the species undergoing disproportionation is

Step-by-step solution

H B r O + 1 → B r 2 0 , E H B r O / B r 2 0 = 1.595 V H B r O + 1 → B r + 5 O 3 - , E B r O 3 - / H B r O 0 = 1.5 V E c e l l 0 for the disproportionation of HBrO, E c e l l 0 = E H B r O / B r 2 0 - E B r O 3 - / H B r O 0 = 1.595 - 1.5 = 0.095 V = + v e Hence, option (C) is correct answer as E c e l l 0 is positive in it.