If E F e 2 + | F e o = - 0.44 V , E F e 3 + | F e 2 + o = 0.77 V . The value of E F e 3 + | F e o is

Step-by-step solution

Fe 2+ +2e − → Fe; ΔG 1 = − 2F − 0 .44 A =ZaCO 3 =FeCO 3 Fe 3+ +e − → Fe 2+ ; ΔG 2 = − F 0 .77 So, Fe 3+ +3e − → Fe;   ΔG   =   − 3F(E)   =   ΔG 1 +ΔG 2 E = - 0.0367 V