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Consider the following relations for emf of an electrochemical cell ( i ) EMF of cell = (oxidation potential of anode) - (Reduction potential of cathode) ( i i ) EMF of cell = (oxidation potential of anode) + (Reduction potential of cathode) ( i i i ) EMF of cell = (reduction potential of anode) + (oxidation potential of cathode) ( i v ) EMF of cell = (oxidation potential of anode) - (oxidation potential of cathode)

Options

  1. A(iii) and (i)
  2. B(i) and (ii)
  3. C(iii) and (iv)
  4. D(ii) and (iv)

Correct answer

D. (ii) and (iv)

Step-by-step solution

EMF of a cell = reduction potential of cathode - reduction potential of anode = reduction potential of cathode + oxidation potential of anode = oxidation potential of anode - oxidation potential of cathode.

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