NTA Abhyas NEET2020ChemistryElectrochemistryPractice
What is the standard cell Potential E Cell o for following cell reaction? 2Fe(s) + O 2 (g) + 2H 2 O(l) ⇌ 2Fe 2+ (aq) + 4OH - (aq) Given E o Fe 2+ (aq) | Fe = − 0 .44 V E o O 2 (g) | H 2 O | OH = 0 .4 V
Options
- AE cell o =  − 0. 48   V
- BE cell o =  − 0 .04   V
- CE cell o = +   0 .84   V
- DE c e l l 0 = + 1.28 V
Correct answer
C. E cell o = +   0 .84   V
Step-by-step solution
2Fe(s)   +   O 2 (g)   +   2H 2 O(l) ⇌ 2Fe 2+ (aq)   +   4OH − (aq) For the given cell reaction E cell o   =   E cathode o − E anode o =   0 .40 − − 0 .44   =   0 .84   V