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NTA Abhyas NEET2020ChemistryElectrochemistryPractice

When 9.65 C of electricity is passed through a solution of silver nitrate (atomic weight of Ag = 107.87 taking as 108), the amount of silver deposited is

Options

  1. A5.8 mg
  2. B10.8 mg
  3. C15.8 mg
  4. D20.8 mg

Correct answer

B. 10.8 mg

Step-by-step solution

w Ag = E Ag × Q 96500 = 108 × 9 .65 96500 = 1 .08 × 10 - 2 g = 10 .8 mg

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