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Reaction: 2 F e 3 + + 3 I - ⇌ 2 F e 2 + + I 3 - The standard reduction potentials in acidic conditions are 0.77 V and 0.54 V respectively for cathodic and anodic reactions. The equilibrium constant for the reaction is approximately.(Given 10 7.79 = 6.26 × 10 7 )

Options

  1. A6.26 × 10 - 7
  2. B5.33 × 10 - 4
  3. C6.26 × 10 7
  4. D5.33 × 10 4

Correct answer

C. 6.26 × 10 7

Step-by-step solution

For the change , 2 F e 3 + + 3 I - ⇌ 2 F e 2 + + I 3 - E c e l l ° = 0.77 - 0.54 = 0.23 V E cell ∘ = 0.059 2 log K C 0.23 = 0.0591 2 log ⁡ K c K c = 6.26 × 10 7

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